Il initially have à gas at a pressure of 12 atm, a volume of 23 liters, and a
temperature of 200 K, and then I raise the pressure to 14 atm and
increase the temperature to 300 K, what is the new volume of the gas?

The new volume of the gas is 29.6 L.

Explanation:

Using the ideal gas equation, we can find the new volume of the gas y cancelling the gas constant and number of moles as both are same in both the cases.

By using the equation,

P1, V1 and T1 are the initial values of Pressure, Volume and temperature of the gas and P2,V2 and T2 are the final values of Pressure, Volume and temperature of the gas.

We have to find the new volume by rearranging the equation as,

     = 29.6 L

So the new volume of the gas is 29.6 L.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.