An air mattress is filled with 0.55 moles of air. The air inside the mattress has a temperature of 295 K and a gauge pressure of 3.5 kilopascals. What is the volume of the air mattress?

385.4132857

Explanation:

Using the equation, PV=nRT, you can solve this problem.

P= 3.5 kPa      V=?    n= 0.55 moles of air     T= 295K    R= 8.314 (L kPa/mol K)

We use the constant rate of 8.314 because we are using kilopascals in this problem.

Using simple algebra we get-

V = (0.55 moles)(8.314 L kPa/mol k)(295 K) / 3.5 kPa

Using the calculator, we would get the answer of 385.4132857 L.

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.

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