What is the mass of lead in 452 g PbCl2?

335.664 grams is the mass of lead in 452 grams of PbCl2.

Explanation:

Data given:

mass of lead in PbCl2 = 452 grams

mass of lead =?

atomic mass of PbCl2 = 278.1 grams/mole

atomic mass of Pb = 207.2 grams/mole

atomic mass of chlorine = 35.45 grams/mole

From the chemical formula of PbCl2 it is deduced that 1 mole of lead chloride contains 1 mole of Pb cation and 2 moles of chloride anion

number of moles of PbCl2 provided are:

number of moles =

number of moles = 1.62 moles of PbCl2 is provided

so when 1 mole of PbCl2 contains 1 mole of lead

then 1.62 moles of PbCl2 will have 1.62 moles of lead

mass = atomic mass x number of moles

mass of lead = 1.62 x 207.2

mass of lead = 335.664 grams

335.664 grams of lead is present in a sample of lead chloride having mass of 452 grams.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j