I need help with chem there are ore questions sides this one
NaCl+AgNO3 →AgCl+NaNO3
how many grams of AgCl will be produced from 7.00 grams of NaCl and 95.0 grams of AgNo3?

The answer to your question is 17.2 g of AgCl

Explanation:

Data

mass of NaCl = 7 g

mass of AgNO₃ = 95 g

mass of AgCl = ?

Balanced chemical reaction

               NaCl  +  AgNO₃  ⇒   AgCl  +  NaNO₃

Process

1.- Calculate the molar mass of the reactants

NaCl = 23 + 35.5 = 58.5 g

AgNO₃ = 108 + 14 + 48 = 170 g

2.- Calculate the limiting reactant

theoretical yield = AgNO₃ / NaCl = 170 / 58.5 = 2.9

experimental yield = AgNO₃ / NaCl = 95 / 7 = 13.6 g

From these results we conclude that the limiting reactant is NaCl because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of AgCl

Molar mass of AgCl = 108 + 35.5 = 143.5 g

-Use proportions

                      58.5 g of NaCl 143.5 g of AgCl

                        7.0 g of NaCl  x

                           x = (7 x 143.5) / 58.5

                           x = 17.2 g of AgCl