Calculate the amount of heat needed to convert 50.0 g of liquid water at to steam at 100ºC.
16,700 J

113,000 J

104 J

209 J

We need 113000 J of heat (option 2 is correct)

Explanation:

Step 1: Data given

Mass of liquid water = 50.0 grams

ΔHVap = 2260 J/g

Temperature = 100 °C

ΔHVap = The amount of heat released to change phase of a liquid water to steam = 2260 J/g

Step 2: Calculate the heat needed

Q =m* ΔHVap

⇒with Q = the amount of heat needed = TO BE DETERMINED

⇒with m = the mass of water = 50.0 grams

⇒with ΔHVap = 2260 J/g

Q = 50.0 grams * 2260 J

Q = 113000 J

We need 113000 J of heat (option 2 is correct)