Using the combined gas law, if the volume of a gas at 155kPa changes from 22L to 10L. What is the new pressure if the temperature remains constant?

The answer to your question is  P2 = 342 kPa

Explanation:

Data

Pressure 1 = P1 = 155 kPa

Volume 1 = V1 = 22 l

Pressure 2 = P2 = ?

Volume 2 = V2 = 10 l

Temperature = constant

Process

1.- Write the equation of the combined gas law

                 P1V1/T1 = P2V2/ T2

Cancel T1 and T2 because they measure the same

                 P1V1 = P2V2

-Solve for P2

                 P2 = P1V1/V2

2.- Substitution

                 P2 = (155 x 22) / 10

3.- Simplification

                 P2 = 3410 / 10

4.- Result

                 P2 = 342 kPa

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products