Use Boyle's, Charles's, or Gay-Lussac's law to calculate the missing value in each of the following.
(a) V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?
atm

(b) V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K
K

(c) V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.84 L, P2 = ?
mm Hg Use Boyle's, Charles's, or Gay-Lussac's law to calculate the missing value in each of the following.
(a) V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?
atm

(b) V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K
K

(c) V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.84 L, P2 = ?
mm Hg

The missing value is found using the Boyle's Law and P2= 1.24 atm

The missing value is found using the Charles 's Law and T1= 171.35

Explanation:

Given data

1. Volume and pressure is given

Based on the data, the volume and pressure is given it requires the  Boyle's Law

Boyle's Law:

P1 V1 = P2V2

Given data

V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

(0.62 atm)(2.0L)= P2 (1.OL)

Dividing both the sides by 1.0L

we get P2= 1.24 atm

The missing value is found using the Boyle's Law and P2= 1.24 atm

2. A volume and temperature is given:

Charles Law:

V1 / T1  = V2 /T2

Given data

V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

230 ml/ T1= 400 ml/ 298 K

T1 × 400 ml = 68450 ml × K

T1= 171.35

The missing value is found using the Charles 's Law and T1= 171.35

you need to give more information

a boiling water reactor does not boil the water. a pressurized water reactor boils the water faster. a pressurized water reactor is heated directly by the core. a pressurized water reactor does not use fission.