A steel container with a volume of 30L is filled with oxygen to a pressure of 9.00 atm at 28.0°C. What is the pressure of the temperature changes to 129.0°C

Explanation:

The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 9.00 atm; T₁ =   28.0 °C

p₂ = ?;              T₂ = 129.0 °C

Calculations:

1. Convert the temperatures to kelvins

T₁ =   (28.0 + 273.15) K = 301.15

T₂ = (129.0 + 273.15) K = 402.15

2. Calculate the new pressure

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)