What volume is occupied by 0.250 mol of carbon dioxide gas at 25°C
and 0.488 atm?
A) 25.5 L B) 12.5L C) 12.5K D) 15.9L

B) 12.5L

Explanation:

-We apply the mixed Gas Law:

Where:

is the given pressure of the gas

is the volume of the gas

is the number of moles of the gas

is the ideal gas constant and temperature respectively.

#We make V the subject of the formula and substitute to solve for it;

Hence, the volume of the gas is 12.5 L

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :