Chemistry, 20.04.2020 19:57 dthompson365

If 0.600 moles of Nitrogen gas is collected at a pressure of 234 kPa in a
container which has a volume of 12.0 L, what is the temperature of the
nitrogen gas in the container? Express the temperature in Kelvin. (use the R
value for kPa)
563.18 K
O 4680 K
O 52 atm
O 337.91K

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Answer from: arivalen

563.18 K

General Formulas and Concepts:

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure (in kPa)L is volume (in L)n is molesR is gas constantT is temperature (in K)

Explanation:

Step 1: Define

[Given] n = 0.600 mol N₂

[Given] P = 234 kPa

[Given] L = 12.0 L

[Given] R = 8.314 L · kPa · mol⁻¹ · K⁻¹

[Solve] T

Step 2: Solve for T

Substitute in variables [Ideal Gas Law]: (234 kPa)(12.0 L) = (0.600 mol)(8.314 L · kPa · mol⁻¹ · K⁻¹)TMultiply: 2808 kPa · L = (4.9884 L · kPa · K⁻¹)T[Division Property of Equality] Isolate temp: T = 562.906 K

Topic: AP Chemistry

Unit: Gas Laws

Answer from: Quest

Is there a diagram/picture you can provide? it seems this question goes along with a

Answer from: Quest

definition

entropy is a measure of the randomness or the extent of disorder of a chemical process.

enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

entropy is measured in joule per kelvin (jk⁻¹) whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

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If 0.600 moles of Nitrogen gas is collected at a pressure of 234 kPa in a
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