When 63.4 g of glycine (C2HNO2 are dissolved in 700. g of a certain mystery liquid X, the freezing point of the solution is 7.9 °C lower than the freezing point of pure X. On the other hand, when 63.4 g of iron(III) chloride are dissolved in the same mass of X, the freezing point of the solution is 13.3 °C lower than the freezing point of pure X Calculate the van't Hoff factor for iron(III) chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits. x 10

3.8 is the van't Hoff factor for iron(III) chloride in X.

Explanation:

where,

=depression in freezing point =

= freezing point constant

m = molality =

i = van't Hoff factor

we have :

Mass of glycine = 63.4 g

Molar mass of glycine = 71 g/mol

Mass of solvent X = 700. g = 0.7 kg

1 g = 0.001 kg

of solvent X= ?

i = 1  (non electrolyte)

Depression in freezing point=

When iron(III) chloride is dissolved in 0.7 kg of solvent X

Mass of  iron(III) chloride = 63.4 g

Molar mass of  iron(III) chloride= 162.5 g/mol

Mass of solvent X = 700. g = 0.7 kg

1 g = 0.001 kg

of solvent X=

i = ?

Depression in freezing point:

Solving for i:

i = 3.85 ≈ 3.8

3.8 is the van't Hoff factor for iron(III) chloride in X.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.