How many moles of MgCl2 are contained in 261.5 mL of a 0.005 M MgCl2 solution? Please show your work.

The answer for the following problem is mentioned below.

Explanation:

Molarity:

The no of moles of moles present in one litre of the solution is called molarity

Given:

molarity of magnesium chloride (m) = 0.005 M

volume of magnesium chloride solution (V) = 261.5 ml

To find:

no of moles of magnesium chloride solution (n)

We know;

molarity =

m =  

where;

m represents the molarity of the magnesium chloride solution

n represents the no of moles of magnesium chloride solution

V represents the volume of magnesium chloride solution

So;

0.005 =

n = 0.005 × 261.5

n = 1.3075 moles

Therefore the no of moles in the magnesium chloride solution is 1.3075 moles.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

i do not get it   at all