1) How much water must be added to 500.mL of 0.200 M HCI to produce a 0.150M solution?

2) If you Dilute 175 mL of a 1.6 M solution of LiCI to 1.0 L, determine the new concentration of the solution.

1)

(500.mL)(.200M)/.150M = 667 mL

667mL - 500mL = 167mL of water is needed

2)

1.0 L = 1000mL

M1 V1 = M2 V2

(1.6 mol/L) (175 mL) = (x)(1000mL)

x = .28M

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)