These questions are on gas laws.

If I had 25.0 grams of methane, how many moles of CH4 would I have?

If I had the above moles of methane in a sealed 1.55 Liter container at 25C, what would be the pressure in the container in the atmosphere?

.If I cooled down the same number of moles in the same container to 12C what would be the pressure in the atmosphere?

Did the pressure in the container increase or decrease? Explain why it happened.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied