Complete each of the following nuclear equations and calculate the energy change (in J/molJ/mol of reactants) associated with each one.
(Al−27=26.981538amu
(Al−27=26.981538amu,
Am−241=241.056822amu
Am−241=241.056822amu,
He−4=4.002603amu
He−4=4.002603amu,
Np−237=237.048166amu
Np−237=237.048166amu,
P−30=29.981801amu
P−30=29.981801amu,
S−32=31.972071amu
S−32=31.972071amu, and
Si−29=28.976495amu.)

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.