In photosynthesis, carbon dioxide and water are converted into glucose and oxygen in the presence of chlorophyll and light energy. If 1.0 mole of water is available with an excess of carbon dioxide, how many moles of glucose (C6H12O6) can be produced

0.17 mole of glucose is formed.

Explanation:

Step 1:

The equation for the reaction. This is given below:

CO2 + H2O —> C6H12O6 + O2

Step 2:

Balancing the equation.

The equation can be balanced as follow:

CO2 + H2O —> C6H12O6 + O2

There are 6 atoms of C on the right side and 1 atom on the left side. It can be balance by putting 6 in front of CO2 as shown below:

6CO2 + H2O —> C6H12O6 + O2

Therefore are 12 atoms of H on the right side and 2 atoms on the left side. It can be balance by putting 6 in front of H2O as shown below:

6CO2 + 6H2O —> C6H12O6 + O2

There are a total of 8 atoms of O the right side and a total of 18 atoms on the left. It can be balance by putting 6 in front of O2 as shown below:

6CO2 + 6H2O —> C6H12O6 + 6O2

Now the equation is balanced.

Step 3:

Determination of the number of mole of glucose (C6H12O6) produced by 1 mole of water.

This is illustrated below:

6CO2 + 6H2O —> C6H12O6 + 6O2

From the balanced equation above,

6 moles of H2O produced 1 mole of C6H12O6.

Therefore, 1 mole of H2O will produce = 1/6 = 0.17 mole of C6H12O6.

IF 1.0 mol of water is available, 0.167 moles of glucose (C6H12O6) will be produced

Explanation:

Step 1: Data given

Number of moles of water = 1.0 moles

Carbon dioxide is in excess

Step 2: The balanced equation

6CO2 + 6H2O → C6H12O6 + 6O2

Step 3: Calculate moles of glucose

For 6 moles CO2 we need 6 moles H2O to produce 1 mol glucose and 6 moles O2

For 1.0 moles of water we'll have 1.00 / 6 = 0.167 moles of glucose

IF 1.0 mol of water is available, 0.167 moles of glucose (C6H12O6) will be produced

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