Phosphorus trifluoride is formed from its elements P4 (s) F2 (g) ---> PF3 (g) how many grams of fluorine are needed to react with 6.20 g

This is an incomplete question, here is a complete question.

Phosphorus trifluoride is formed from its elements.

How many grams of fluorine are needed to react with 6.20 g of phosphorus?

Answer : The mass of needed are, 11.4 grams.

Explanation : Given,

Mass of = 6.20 g

Molar mass of = 124 g/mol

Molar mass of = 38 g/mol

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical equation is:

From the balanced reaction we conclude that

As, 1 mole of react with 6 moles of

So, 0.05 moles of react with moles of

Now we have to calculate the mass of

Therefore, the mass of needed are, 11.4 grams.

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation: