In a precipitation reaction (otherwise known as a double replacement or metathesis reaction) the extent to which a precipitate is formed is dependent on the solubility product constant of the precipitate. A species with a large Ksp (highly soluble) may not precipitate until very high concentrations are reached. A species with a low Ksp (mostly insoluble) will precipitate readily. Use the ideas explored in this activity to explain why the formation of a precipitate may increase when non-stoichiometric amounts of reactants are used (one reactant will limit, while the other will be in excess).

It dont even matter because at the end of thre day we gone life like it ius s

There is no reason to think the results are biased or not conducted properly but you should not assume the results are correct just because they were done in a laboratory so the answer would be c. it is likely to be reliable because the results support the conclusion presented.

Your question is not clear but if you can explain yourself i would be glad to .  just trying to : ))

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.