Suppose that 10.1 mL of HNO, is neutralized
by 71.4 mL of a 4.2 x 10-3 M solution of KOH
in a titration. Calculate the concentration of
the HNO3 solution.

i ahev no idea what this even means even tho i am in college

Explanation:

answer; i believe that the correct answer is (a) potassium(k)

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml