Imagine some radish plants are planted too close. they are well- fed and well- watered. why might they be growing to be tall and spindly?

Due to plantation of some radish plants too closely, they compete with each other for nutrients and water. So, they grow long and thin.

Explanation:

Radishes grows tall and spindly due to hot weather, unfit soil, and conflict with other plants. More nitrogen in the soil may also cause radishes to grow long and thin.

Radishes sometimes grow “out of the ground” because either the soil is compacted or the seeds were planted too shallow.

Radishes, like carrots, prefer to grow in loose, sandy soil.  This means that the soil should be smooth, with no rocks, roots, or dirt clumps.

Due to competition with other plants (including nearby radishes!)  When there are too many plants in one area, they will compete with one another for nutrients and water.

In addition, when radishes are planted too close together, the roots physically have nowhere to go.  Since they cannot grow wider, they instead grow longer, going deeper into the soil in search of nutrients and water.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"