1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?

Answer : The number of molecules present in nitrogen gas are,

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

where,

P = Pressure of gas =      (1 atm = 760 mmHg)

V = Volume of gas = 985 mL = 0.982 L    (1 L = 1000 mL)

n = number of moles  = ?

R = Gas constant =

T = Temperature of gas =

Now put all the given values in above equation, we get:

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains number of molecules.

As, 1 mole of gas contains number of molecules

So, mole of gas contains number of molecules

Therefore, the number of molecules present in nitrogen gas are,

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: