Ethylene (C2H4 = 28.05 g/mol) burns in oxygen (O2 = 32 g/mol) to form carbon dioxide (CO2
= 44.01 g/mol) and water vapor (H20 = 18.02 g/mol):
C2H4(9) + 3 O2(g) → 2 CO2(g) + 2 H2O(g)
How many liters of carbon dioxide can be formed if 4.93 liters of ethylene are consumed in
this reaction (at STP) with excess O2?
Select one:

9.54L
9.86L
2.31L
5.83L