A gas has a volume of 4.54 L at 1.65 atm and 75. I decrease celsius. At what pressure would the volume of the gas be increased to 5.33 L if the temperature is increased to 103 degrees Celsius?

The answer to your question is P2 = 1.52 atm

Explanation:

Data

Volume 1 = V1 = 4.54 l

Pressure 1 = P1 = 1.65 atm

Temperature 1 = T1 = 75°C

Volume 2= V2 = 5.33 l

Pressure 2 = P2 = ?

Temperature 2 = 103°C

Process

1.- Convert temperature to °K

Temperature 1 = 75 + 273 = 348°K

Temperature 2 = 103 + 273 = 376°K

2.- Use the combine gas law to find the final pressure

               P1V1/T1 = P2V2/T2

-Solve for P2

               P2 = P1V1T2 / T1V2

-Substitution

               P2 = (1.65 x 4.54 x 376) / (348 x 5.33)

-Simplification

               P2 = 2816.62 / 1854.84

-Result

              P2 = 1.52 atm

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