A solution has pOH 5.9
A) What is the [OH-]?
B) What is the [H3O+]?
C) Is this acidic, alkaline, or neutral?

The answer to your question is below

Explanation:

Data

pOH = 5.9

a) [OH⁻] = ?

pOH measures the [OH⁻]

Formula

pOH = -log[OH⁻]

-Substitution

5.9 = -log[OH⁻]

[OH⁻] = antilog (-5.9)

-Result

[OH⁻] = 1.26 x 10⁻⁶ M

b) [H₃O⁺]

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

-Substitution

pH = 14 - 5.9

-Result

pH = 8.1

-Calculate [H₃O⁺]

pH = -log[H₃O⁺]

-Substitution

8.1 = -log[H₃O⁺]

[H₃O⁺] = antilog(-8.1)

-Result

[H₃O⁺] = 7.9 x 10⁻⁹ M

c) This solution is alkaline because the pH is higher than 7.

particle   p is an electron and particle q is a neutron