If you have 39.5g of Fe2O3 how many grams of co are requried to complete reaction

Explanation:

1. Balanced chemical equation

2. Convert 39.5g of Fe₂O₃ into moles

3. Moles of CO

i) Mole ratio

ii) Set a proportion

     ⇒ x = 0.24735mol Fe₂O₃ × 3mol CO / 1mol Fe₂O₃ = 0.7426 mol CO

4. Grams of CO

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.