Chemistry, 05.10.2019 17:30 7thaohstudent

2.15 g of an unknown gas at 71 degrees c and 1.10 atm is stored in a 1.75 l flask. solve for the density and the molar mass of the gas.

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Answer from: hella33revj

Density : 0.01229 g/ml

Molar mass : 31.525 g/mol

Further explanation

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:

Boyle's law at constant T, P = 1 / V Charles's law, at constant P, V = T Avogadro's law, at constant P and T, V = n

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

2.15 g of an unknown gas at 71 degrees C and 1.10 atm is stored in a 1.75 L flask.

so density = mass : volume

$\rm density=\rho=\dfrac{21.5}{1750}=\boxed{0.01229\dfrac{g}{ml}}$

To find the molar mass, we first look for the number of moles with the ideal gas equation:

PV = nRT

T = 71 °C + 273 = 344 K

$\rm n=\dfrac{PV}{RT}\\\\n=\dfrac{1.10\times 1.75}{0.08206\times 344}\\\\n=\boxed{0.0682}$

$\rm molar\:mass=\dfrac{mass}{mol}\\\\molar~mass=\frac{2.15}{0.0682}\\\\molar\:mass=\boxed{\bold{31.525\:\dfrac{g}{mol} }}$

Learn more

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Answer from: Quest

i believe the answer is c. "baking" is the gerund, while "baking blueberry muffins" would be the gerund phrase. hope this ! : )

Answer from: Quest

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

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