What is the mass of 2.35 moles of (NH4)3PO4?

The mass of 2.35 moles of (NH4)3PO4 is 411.156 or 411.156 grams/g.

Explanation:

By calculating the mass of the formula, (NH4)3PO4, which equals up to 174.96 grams you divide 2.35 moles by 174.96 grams to equal 411.156 grams. The way to find out the mass is to multiple the molar mass of each chemical to the number beside it such as H multiplied by 4, P multiplied by 3, and so on.

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