For a hydrogen- like atom, classify these electron transitions by whether they result in the absorption or emission of light:
n=3 to n=5,
n=1 to n=3,
n=3 to n=2,
n=2 to n=1?
ignoring the sign, which transition was associated with the greatest energy change?

When an electron transit from lower level to higher level it emits energy

When an electron transit from higher level from a lower level it absorbs energy

n=3 to n=5,  : absorption

n=1 to n=3,  : absorption

n=3 to n=2,  : emission

n=2 to n=1 : emission

the highest energy means highest wave number

wave number = Rh (1/ n1^2 - 1/n2^2)

Rh = 1.1 X 10^7 m^-1

1) n=3 to n=5

wavenumber = Rh ( 1/ 9 - 1/ 25) = 0.071 Rh

2) n=1 to n=3

wavenumber = Rh ( 1- 1/9 ) = 0.89 Rh

3) n=3 to n=2

wavenumber = Rh ( 1/4 - 1/9) = 0.139 Rh

4) n=2 to n=1

wavenumber = Rh ( 1- 1/4) = 0.75 Rh

Thus for 2) n=1 to n=3 energy will be maximum

elements make up everything, and they combine to make compounds.

the answer is c

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2