Please help
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313K.

Thank you

c = .137 J/g

Explanation:

q = mcΔT, where q=heat, m=mass, c=specific heat, ΔT=change in temp.

q = 96 J

m = 35 g

c = ?

ΔT = Tfinal - Tinitial = 313 - 293 K = 20 K

q = mcΔT

96 = 35c*20

96 = 700c

c = .137 J/g

a sequence is a function whose domain is the set of natural numbers.

natural numbers are all the negative and positive integers

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8