A balloon now occupies 9.7L at 25.0°C and 1.00 atm. What temperature was it initially, if it occupied 9.0 L and was in a freezer with a pressure of 0.92 atm?

-19°C (2 sig.figs.)

Explanation:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = 1.00atm

V₁ = 9.7L

T₁ = 25°C = 298K

P₂ = 0.92atm

V₂ = 9L

T₂ = ?

T₂ = T₁P₂V₂/P₁V₁

= 298K(0.92atm/1.00atm)(9.0L/9.7L) = 254K = (254 - 273)°C = -19°C (2 sig.figs.)

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.