A sample of a gas occupies 1.80 L at -10. °C and 450. Torr. What will be the temperature if the pressure is increased to 800. Torr and the volume is decreased by 1/3?

156 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 450 torr

= final pressure of gas = 800 torr

= initial volume of gas = 1.80 L

= final volume of gas =

= initial temperature of gas =

= final temperature of gas = ?

Now put all the given values in the above equation, we get:

Thus the final temperature will be 156 K

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.  

∠gdh and ∠edh on edg.

answer is c