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How much heat does an aluminum block absorb if 10.00 grams are heated from 25.0˚C to 50˚C? The specific heat of aluminum is .900 j/g ˚C
(2 Points)
450
225
-450
-225

Explanation:

Heat flow equation => q = m·c·ΔT

m = mass in grams = 10.00 grams

c = specific heat (a constant) = 0.900j/g·°C

ΔT = temperature change in °C = 50°C - 25°C = 25°C

q = (10.00g)(0.900j/g·°C)(25°C) = 225 joules absorbed*

*absorbed => endothermic process => need to show 'plus' energy change.

If the reactions were an exothermic process the problem would use terms like energy released, energy lost, energy given-up, etc... => would require using a 'negative' signage before the calculated energy value. So, the correct choice is the +225 joules value.

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