If 1.332 mol of C4H10 are reacted with 6.504 mol of O2, how many mol of the excess reagent will remain unreacted? 2 C4H10 + 13 O2 ——> 8 CO2 + 10 H2O MM: 58.1 32.0 44.0 18.0

The number of moles of excess reagent remain unreacted will be, 6.004 moles.

Explanation : Given,

Moles of = 1.332 mol

Mass of = 6.504 mol

First we have to calculate the limiting and excess reagent.

The balanced chemical equation is:  

From the balanced reaction we conclude that

As, 13 mole of react with 1 mole of

So, 6.504  moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol

Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.

the volume increases

the awnser is group 12