Your cousin is preparing a classic volcano for her school's science project using baking soda and vinegar, but she is disappointed that her volcano is not as exciting as the one she saw online. Knowing that you're taking chemistry, she asks for your help. Based on what you learned in experiment 2, which of the following changes is likely to result in the most exciting volcano?A. Combining the reactants in their stoichiometric ratio to ensure maximum production of product.
B. Adding excess vinegar to drive the reaction equilibrium toward products.
C. Using more baking soda, because it is responsible for producing the CO2 gas that erupts from the volcano.
D. Forming the baking soda into a cube so it will react all at once.

Explanation:

Carbonic acid (H2CO3) is formed when vinegar (CH3COOH) and baking soda (NAHCO3) are mixed which is unstable and decomposes to produce CO2. This is what will make the bubble rise and fizz steadily to the top of the volcano.

CH3COOH + NAHCO3 ⇄  CH3COONa + H2CO3

H2CO3 ⇒  H2O + CO2

Vinegar is dilute Acetic acid, the reaction equilibrium will be shifted to the product side upon the addition of more vinegar. Hence, more H2CO3 will form, that is more CO2 will form. This would lead to more bubbles arising.

Therefore,  the answer is option B - adding excess vinegar to drive the reaction equilibrium to the product side.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2