You have the equations:

2H2O(l)→2H2(g)+O2(g), △H=572 kJ

2N2(g)+3H2(g)→2NH3(g), △H=−138 kJ

2NO2(g)+7H2(g)→2NH3(g)+4H2O(l), △H=−1.18×103 kJ 2NO2(g)→2N2(g)+2O2(g), △H=□

What is the missing △H ?

−1.38×103 kJ

+99.0 kJ

+1.38 × 10³ kJ

−138 kJ

the answer is 99.0kJ

Explanation:

I took the test in chemistry

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.