Balance each of the chemical equations below. (Some equations may already be
in balance.) In the space to the right, classify the reaction as a synthesis, decomposition,
single replacement, or double replacement reaction.
A. ___ AgNO3 + ___ KCl⇒ ___ AgCl + ___ KNO3
B. ___ H2O + ___ SO3 ⇒ ___ H2SO4
C. ___ KI + ___ Cl2 ⇒ ___ KCl + ___ I2
D. ___ NaHCO3 ⇒___ Na2CO3 + ___ H2O + ___ CO2
E. ___ Zn + ___ HCl ⇒ ___ ZnCl2 + ___ H2
F. ___ BaCl2 + ___ Na2SO4 ⇒ ___ BaSO4 + ___ NaCl
G. ___ C3H8 + ___ O2 ⇒ ___ CO2 + ___ H2O
H. ___ Al + ___ CuCl2 ⇒ ___ AlCl3 + ___ Cu

i will give 80 points and brainliest answer to the first one that answers

A. 1 AgNO3 + 1 KCl ⇒ 1 AgCl + 1 KNO3 double replacement

B. 1 H2O + 1 SO3 ⇒ 1 H2SO4 synthesis

C. 2 KI + 1 Cl2 ⇒ 2 KCl + 1 I2 single replacement

D. 2 NaHCO3 ⇒ 1 Na2CO3 + 1 H2O + 1 CO2 decomposition

E. 1 Zn + 2 HCl ⇒ 1 ZnCl2 + 1 H2 single replacement

F. 1 BaCl2 + 1 Na2SO4 ⇒ 1 BaSO4 + 2 NaCl double displacement

G. 1 C3H8 + 5 O2 ⇒ 3 CO2 + 4 H2O combustion

H. 2 Al + 3 CuCl2 ⇒ 2 AlCl3 + 3 Cu single displacement

Explanation:

Use algebra to make sure you have the same amount of each element on each side (Reactants and Products) and only change the coefficients of the compounds and elements!

double displacement: AB + CD ⇒ AD + CB

single replacement: AB + C ⇒ A + CB

decomposition: A ⇒ B + C

synthesis: A + B ⇒ C

combustion: any reaction that involve oxygen and don't follow any of the previous reactions

a police officer and a ambulance

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole