A reaction between liquid reactants takes place at 30.0 °C in a sealed, evacuated vessel with a measured volume of 20.0 L. Measurements show that the reaction produced 17. g of carbon monoxide gas. Calculate the pressure of carbon monoxide gas in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round your answer to 2 significant digits.

The pressure of the carbon monoxide gas is 0.75 atm

Explanation:

Step 1: Data given

Temperature = 30.0 °C = 303 K

Volume = 20.0 L

MAss of carbon monoxide gas = 17.0 grams

Molar mass of CO = 28.01 g/mol

Step 2: Calculate moles CO

Moles CO = mass CO / molar mass CO

Moles CO = 17.0 grams / 28.01 g/mol

Moles CO = 0.607 moles

Step 3: Calculate the pressure of the carbon monoxide gas

p*V = n*R*T

⇒with p = the pressure of the carbon monoxide gas = TO BE DETERMINED

⇒with v = the volume of the vessel = 20.0 L

⇒with n = the number of moles of CO = 0.607 moles

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 303 K

p = (n*R*T) / V

p = (0.607 moles * 0.08206 L*atm/mol*K * 303 K) / 20.0 L

p = 0.754 atm ≈ 0.75 atm

The pressure of the carbon monoxide gas is 0.75 atm

a rain shadow is a dry region of land on the side that is protected against the prevailing winds of a mountain range. the prevailing winds are the winds that occur most of the time in a particular place of the earth

prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).