A stock solution of HNO3HNO3 is prepared and found to contain 12.7 M of HNO3HNO3. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is M.

The concentration of the diluted solution is 0.635 M.

Explanation:

The given data is as follows.

          = 12.7 M,       = 25.0 ml = 0.025 L  (as 1 ml = 0.001 L)

          = ? ,       = 0.5 L

Therefore, we will calculate the molarity of the solution as follows.

            = 0.635 M

Thus, we can conclude that the concentration of the diluted solution is 0.635 M.

c. is the answer

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