A marshmallow has an initial volume of 0.027 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.205L, what is the pressure inside the chamber?

A marshmallow has an initial volume of 0.027 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.205L, what is the pressure inside the chamber?

The pressure inside the chamber is 0.132 atm

Explanation:

Step 1: Data given

The initial volume = 0.027 L

The initial pressure = 1.0 atm

The volume changes to 0.205 L

Step 2: Calculate the pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.0 atm

⇒with V1 = the initial volume = 0.027 L

⇒with P2 = the changed pressure = TO BE DETERMINED

⇒with V2 = the changed volume = 0.205 L

1.0 atm *0.027 L = P2*0.205 L

P2 = 0.027/0.205

P2 = 0.132 atm

The pressure inside the chamber is 0.132 atm

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.

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