A rigid container holds a gas at a pressure of 55kPa and a tempature of -100 C. what will the pressure be when the tempature is increased to 200 C

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Explanation:

Hi there,

This question is employing the Gas Laws, specifically the relationship between internal gaseous pressure and temperature, when volume and gas quantity are constant; Gay-Lussac's Law:

or

However, we will need to convert the pressures and temperatures into standard units. Pressure must be put in terms of (atm) and temperature in Kelvin (K).

Now, solve for as this is what was asked for:

If needed, convert back into kPa, so 1.484 * 101.3 kPa = 150.3 kPa.

thanks,