How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?

The mass of oxygen gas is 22.66 grams

Explanation:

Step 1: Data given

Volume of tank = 2.3 L

Pressure = 7.5 atm

Temperature = 24.0°C = 273 +24 = 297 K

Step 2: Calculate moles oxygen gas

p*V = n*R*T

⇒with p = the pressure of the oxygen gas = 7.5 atm

⇒with V = the volume of the tank : 2.3 L

⇒with n = the moles of oxygen gas = TO BE DETERMINED

⇒with R = the gas constant = 0.08206L*atm/mol*K

⇒with T = the temperature = 297 K

n = (p*V- / (R*T)

n = (7.5 atm * 2.3L) / (0.08206 L*atm/mol*L * 297K)

n = 0.708 moles

Step 3: Calculate mass of oxygen gas

Mass O2 = moles O2 = molar mass O2

Moles O2 = 0.708 moles * 32.0 g/mol

Moles O2 = 22.66 grams

The mass of oxygen gas is 22.66 grams

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