75.0 g of sodium completely reacts with iron III Carbonate. How many grams of sodium carbonate are formed?

mass = 172.78 grams Na₂CO₃(s) formed

Explanation:

6Na°(s) + Fe₂(CO₃)₃ => 3Na₂CO₃(s) + 2Fe°(s)

moles Na°(s) = 15g/23g/mol = 3.26 mole Na°(s)

From stoichiometry of reaction equation, 3.26 mole Na°(s) => 3/6(3.26) mole Na₂CO₃(s) = 1.63 mole Na₂CO₃(s) x 106 g/mole = 172.78 grams Na₂CO₃(s)

the dependant variable is spilled water

the independent is the heat

fe 55.85 g/mol and h2o 18.02 g/mol.