A balloon of air occupies 10.0L(V2)at25.0°C(T2)and1.00atm(P2) . What temperature (T1) was it initially, if it occupied 9.40 L (V1) and was in a freezer with a pressure of 0.939 atm (P1)?

The initial temperature was 263 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 0.939 atm

= final pressure of gas = 1.00 atm

= initial volume of gas = 9.40 L

= final volume of gas = 10.0 L

= initial temperature of gas = ?

= final temperature of gas =

Now put all the given values in the above equation, we get:

Thus the initial temperature was 263 K

the answer is 0.42 is that is an option. this question provides no info