A stock solution of 1.00 M Fe2(SO4)3 is available. How many milliliters are
needed to make 0.500 L of 0.750 M?

375 mL

Explanation:

M1*V1 = M2*V2

M1 = 1.00 M

V1 = ?

M2 = 0.750 M

V2 = 0.500 L

1.00 M * V1 = 0.750 M * 0.500 L

V1 = 0.750*0.500/1.00 = 0.375 L = 375 mL

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o