9.) 4NH +50 ->4NO + 6H0
If 4.8 L of O, are used how many liters of NO and water are formed?

A. 3.2L of NO

B. 4.8L of H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

4NH3 + 5O2 —> 4NO + 6H2O

A. Determination of the litres of NO produced from the reaction. This is illustrated below:

From the balanced equation above,

5L of O2 produced 4L of NO.

Therefore, 4L of O2 will produce = (4x4)/5 = 3.2L of NO.

B. Determination of the litres of H2O produced from the reaction. This is illustrated below:

From the balanced equation above,

5L of O2 produced 6L of H2O.

Therefore, 4L of O2 will produce = (4x6)/5 = 4.8L of H2O

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