At 42°C, what is the fraction of collisions with energy equal to or greater than an activation energy of 83.40 kJ/mol? Give your answer in scientific notation.

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: i hope this . =)