In a molecule of water, how many electrons are shared between each hydrogen atom and an oxygen atom? a. one b. two c. four

solution:

answer is two

explanation:

In sharing of electrons in the equation water each carbon atom and hydrogen atom share its one electron from its outermost orbit.

since carbon has seven electrons in its outermost orbit and it wants to get one electron to complete its octet.

while hydrogen atoms has one electron to its outermost orbit and it needs one electron to complete its duet.

similarly

second hydrogen atom do as the shame process as it also share one electron to carbon to complete its duet.

after the sharing of electrons both the atoms form molecule water which is stable.

sry but any answer choices

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%