A student mixes two water solutions with an initial temperature of 25 degrees Celsius to form a final solution with a mass of 65.0 g at 30.0 degrees Celsius. What is the heat change in kJ for this reaction

Heat change = 3.77kJ

Explanation:

T1 = 25°C

Mass = 65g

T2 = 30°C

specific heat capacity of water = 4.184J/g°C

Heat energy = ?

Heat energy = MC∇T

Heat energy (Q) = MC(T2 - T1)

Q = 65 * 4.184 * (30 - 15)

Q = 251.04 * 15

Q = 3765.6J

Q = 3.77KJ

The heat change during the reaction was 3.77kJ

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