How many moles of cacl2 will be produced from 3.572 g of ca(oh)2 reacting with hcl

0.04821 mol CaCl₂ will be produced from 3.572 g of reacting with HCl.

Reaction:-

 Ca(OH)₂  +  2 HCl  ⇒  CaCl₂  +  H₂O

The ratio of the compounds is 1:1 because we are converting from  Ca(OH)₂ to CaCl₂. There are no numbers in front of Ca(OH)₂  and CaCl₂ because we are converting from  Ca(OH)₂ to CaCl₂.

Now, convert grams of Ca(OH)₂ to moles of Ca(OH)₂.  The molar mass of Ca(OH)₂ is 74.09 g/mol.

Hence, the 0.0482 moles of CaCl₂ will be produced.

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0.04821 mol CaCl₂

Explanation:

Ca(OH)₂  +  2 HCl  ⇒  CaCl₂  +  H₂O

This is your reaction.

We need the chemical equation to know the stoichiometry (the numbers that in front of the compounds).  Since we are converting from Ca(OH)₂ to CaCl₂, you only need to focus on these compounds.  There are no numbers in front of Ca(OH)₂ and CaCl₂, so the ratio of the compounds is 1:1.

Now, convert grams of Ca(OH)₂ to moles of Ca(OH)₂.  The molar mass is 74.09 g/mol.

Using moles of Ca(OH)₂ and the ratio from the stoichiometry, convert moles of Ca(OH)₂ to moles of CaCl₂.  Since the ratio is 1:1, the moles will be equal.

You will produce 0.04821 moles of CaCl₂.