For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when the concentration of NO2 is twice the concentration of O2 gas? For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when the concentration of NO2 is twice the concentration of O2 gas? 4.2 × 10-10 M 2.1 × 10-10 M 2.4 × 109 M 4.8 × 109 M 1.7 x 10 -9 M

Concentration of N₂ is 4.8. M.

Explanation: is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For

N2(g) + 2 O2(g) ⇄ 2 NO2(g)

=

From the question concentration of NO2 is twice of O2:

[NO2] = 2[O2]

Substituting this into :

=

8.3. =

[N2] =

[N2] =

[N2] = 4.8.

The concentration of N2 in the equilibrium is [N2] = 4.8.M.

answer: c.

explanation:

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